What is the answer to solvefor b,ln(2b)=4ln(4b) ?

The answer to solvefor b,ln(2b)=4ln(4b) is b= 1/(e^{\frac{7ln(2)){3}}}

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solvefor b,ln(2b)=4ln(4b)

solve for

b, ln (2 b) = 4 ln (4 b)

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Decimal Notation

b = 0.19842 \dots

Solution steps

ln (2 b) = 4 ln (4 b)

Apply log rules

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

lo g_{10} (2) + 1 = lo g_{10} (x)

lo g_{2} (x + 3) + lo g_{4} (5 - x) = 3

\frac{5 lo g _{2} ( x - 2 )}{3} = 6

lo g_{2} (x) + lo g_{2} (4 x) = 12

lo g_{8} (x - 8) + lo g_{8} (7) = 2

What is the answer to solvefor b,ln(2b)=4ln(4b) ?
The answer to solvefor b,ln(2b)=4ln(4b) is b= 1/(e^{\frac{7ln(2)){3}}}