What is the answer to log_{2}(x)+log_{2}(4x)=12 ?

The answer to log_{2}(x)+log_{2}(4x)=12 is x=32

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log_{2}(x)+log_{2}(4x)=12

lo g_{2} (x) + lo g_{2} (4 x) = 12

x = 32

Solution steps

lo g_{2} (x) + lo g_{2} (4 x) = 12

Apply log rules

x = 32

Verify Solutions:

x = 32

True

The solution is

x = 32

lo g_{8} (x - 8) + lo g_{8} (7) = 2

lo g_{a} (4) = 1.585, lo g_{a} (36)

lo g_{e} (x + 2) = 3

lo g_{2} (5 x + 2) = 3

lo g_{6} (x - 4) + lo g_{6} (x - 5) = 1

What is the answer to log_{2}(x)+log_{2}(4x)=12 ?
The answer to log_{2}(x)+log_{2}(4x)=12 is x=32
Solve for x: log_{2}(x)+log_{2}(4x)=12
The solution is x=32