What is the answer to 0=log_{3}(6t+27)-5 ?

The answer to 0=log_{3}(6t+27)-5 is t=36

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0=log_{3}(6t+27)-5

0 = lo g_{3} (6 t + 27) - 5

t = 36

Solution steps

0 = lo g_{3} (6 t + 27) - 5

Switch sides

lo g_{3} (6 t + 27) - 5 = 0

Move

5

to the right side

lo g_{3} (6 t + 27) = 5

Apply log rules

6 t + 27 = 243

Solve

6 t + 27 = 243 : t = 36

t = 36

Verify Solutions:

t = 36

True

The solution is

t = 36

11200 = 2100 \cdot lo g_{10} (x + 1)

lo g_{10} ((x + 1)^{2}) = 4

lo g_{32} (x) = \frac{4}{5}

y + lo g_{10} (y) = 10

3 lo g_{b} (a - x) = a + c

What is the answer to 0=log_{3}(6t+27)-5 ?
The answer to 0=log_{3}(6t+27)-5 is t=36
Solve for t: 0=log_{3}(6t+27)-5
The solution is t=36