What is the answer to log_{10}(9x)=log_{3}(3x) ?

The answer to log_{10}(9x)=log_{3}(3x) is x=10^{(log_{10}(3)-2log_{10}(3)^2)/(log_{10)(3)-1}}

Solve for x: log_{10}(9x)=log_{3}(3x)

The solution is x=10^{(log_{10}(3)-2log_{10}(3)^2)/(log_{10)(3)-1}}

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lo g_{10} (9 x) = lo g_{3} (3 x)

x = 1 0^{\frac{l o g _{10} ( 3 ) - 2 l o g _{10} ( 3 ) ^{2}}{l o g _{10} ( 3 ) - 1}}

Decimal Notation

x = 0.90833 \dots

Solution steps

lo g_{10} (9 x) = lo g_{3} (3 x)

Apply log rules

x = 1 0^{\frac{l o g _{10} ( 3 ) - 2 l o g _{10} ( 3 ) ^{2}}{l o g _{10} ( 3 ) - 1}}

Verify Solutions:

x = 1 0^{\frac{l o g _{10} ( 3 ) - 2 l o g _{10} ( 3 ) ^{2}}{l o g _{10} ( 3 ) - 1}}

True

The solution is

x = 1 0^{\frac{l o g _{10} ( 3 ) - 2 l o g _{10} ( 3 ) ^{2}}{l o g _{10} ( 3 ) - 1}}

lo g_{3} (z) = - 5

ln (lo g_{2} (a - 3)) = lo g_{3} (1)

2 lo g_{3} (y - 2) - lo g_{3} (y - 4) = 2

lo g_{16} (x) = - \frac{1}{2}

- 5 = lo g_{10} (x)

What is the answer to log_{10}(9x)=log_{3}(3x) ?
The answer to log_{10}(9x)=log_{3}(3x) is x=10^{(log_{10}(3)-2log_{10}(3)^2)/(log_{10)(3)-1}}
Solve for x: log_{10}(9x)=log_{3}(3x)
The solution is x=10^{(log_{10}(3)-2log_{10}(3)^2)/(log_{10)(3)-1}}