What is the answer to log_{6}(3x^2-3x)=2 ?

The answer to log_{6}(3x^2-3x)=2 is x=4,x=-3

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log_{6}(3x^2-3x)=2

lo g_{6} (3 x^{2} - 3 x) = 2

x = 4, x = - 3

Solution steps

lo g_{6} (3 x^{2} - 3 x) = 2

Apply log rules

3 x^{2} - 3 x = 36

Solve

3 x^{2} - 3 x = 36 : x = 4, x = - 3

x = 4, x = - 3

lo g_{10} (x - 3) 9 = 2

lo g_{3} (6 x) + lo g_{3} (2) = 3

x, ln (y) = - 3 ln (x) + c

lo g_{3} (4 x + 10) = lo g_{3} (x + 1)

\frac{ln ( 2 x - 5 )}{2} = 6

What is the answer to log_{6}(3x^2-3x)=2 ?
The answer to log_{6}(3x^2-3x)=2 is x=4,x=-3
Solve for x: log_{6}(3x^2-3x)=2
The solution is x=4,x=-3