What are the solutions to the equation 290=x^2+1 ?

The solutions to the equation 290=x^2+1 are x=17,x=-17

Find the zeros of 290=x^2+1

The zeros of 290=x^2+1 are x=17,x=-17

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290 = x^{2} + 1

x = 17, x = - 17

Solution steps

290 = x^{2} + 1

Switch sides

x^{2} + 1 = 290

Move

1

to the right side

x^{2} = 289

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 289, x = - 289

289 = 17

- 289 = - 17

x = 17, x = - 17

- 2 x^{2} + 10 x + 23 = 0

2 x + 3 (x - 4)^{2} = 37 + (x - 3) (x + 3)

5175

2 x^{2} - 4 x + 5 = 0

6 g^{3} + 18 g^{2} + 5 g + 15

What are the solutions to the equation 290=x^2+1 ?
The solutions to the equation 290=x^2+1 are x=17,x=-17
Find the zeros of 290=x^2+1
The zeros of 290=x^2+1 are x=17,x=-17