What is the answer to 20+ln(5)=2ln(x) ?

The answer to 20+ln(5)=2ln(x) is x=e^{(20+ln(5))/2}

Solve for x: 20+ln(5)=2ln(x)

The solution is x=e^{(20+ln(5))/2}

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20 + ln (5) = 2 ln (x)

x = e^{\frac{20 + l n ( 5 )}{2}}

Solution steps

20 + ln (5) = 2 ln (x)

Switch sides

2 ln (x) = 20 + ln (5)

Divide both sides by

2

ln (x) = \frac{20 + ln ( 5 )}{2}

Apply log rules

x = e^{\frac{20 + l n ( 5 )}{2}}

Verify Solutions:

x = e^{\frac{20 + l n ( 5 )}{2}}

True

The solution is

x = e^{\frac{20 + l n ( 5 )}{2}}

lo g_{8} (lo g_{5} (x)) = 0

0 = 80 - 10 lo g_{2} (t + 1)

lo g_{x} (\frac{1}{125}) = - 9

lo g_{10} (x + 3) = 0

0.74 = ln (y)

What is the answer to 20+ln(5)=2ln(x) ?
The answer to 20+ln(5)=2ln(x) is x=e^{(20+ln(5))/2}
Solve for x: 20+ln(5)=2ln(x)
The solution is x=e^{(20+ln(5))/2}