What is the answer to 0=80-10log_{2}(t+1) ?

The answer to 0=80-10log_{2}(t+1) is t=255

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0=80-10log_{2}(t+1)

0 = 80 - 10 lo g_{2} (t + 1)

t = 255

Solution steps

0 = 80 - 10 lo g_{2} (t + 1)

Switch sides

80 - 10 lo g_{2} (t + 1) = 0

Move

80

to the right side

- 10 lo g_{2} (t + 1) = - 80

Divide both sides by

- 10

lo g_{2} (t + 1) = 8

Apply log rules

t + 1 = 256

Solve

t + 1 = 256 : t = 255

t = 255

Verify Solutions:

t = 255

True

The solution is

t = 255

lo g_{x} (\frac{1}{125}) = - 9

lo g_{10} (x + 3) = 0

0.74 = ln (y)

- 2 = lo g_{0.1} (x)

lo g_{2} (2 x - 3) = lo g_{2} (7)

What is the answer to 0=80-10log_{2}(t+1) ?
The answer to 0=80-10log_{2}(t+1) is t=255
Solve for t: 0=80-10log_{2}(t+1)
The solution is t=255