What is the answer to log_{10}((x+1)/2)=3 ?

The answer to log_{10}((x+1)/2)=3 is x=1999

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log_{10}((x+1)/2)=3

lo g_{10} (\frac{x + 1}{2}) = 3

x = 1999

Solution steps

lo g_{10} (\frac{x + 1}{2}) = 3

Apply log rules

\frac{x + 1}{2} = 1 0^{3}

Multiply both sides by

2

\frac{x + 1}{2} \cdot 2 = 1 0^{3} \cdot 2

Simplify

x + 1 = 2000

Solve

x + 1 = 2000 : x = 1999

x = 1999

Verify Solutions:

x = 1999

True

The solution is

x = 1999

lo g_{10} (3 x) = ln (x)

ln (x - 2) = 3 ln (2) + 2

2 ln (x + 3) - ln (x) = ln (x + 3 a)

y, ln (y) = - 6 x^{2}

lo g_{4} (5 x + 4) - lo g_{4} (4 - x) = 1

What is the answer to log_{10}((x+1)/2)=3 ?
The answer to log_{10}((x+1)/2)=3 is x=1999
Solve for x: log_{10}((x+1)/2)=3
The solution is x=1999