What is the answer to log_{2}(x)-log_{2}(x+1)=2 ?

The answer to log_{2}(x)-log_{2}(x+1)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(x)-log_{2}(x+1)=2

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x) - lo g_{2} (x + 1) = 2

No Solution for x \in R

Solution steps

lo g_{2} (x) - lo g_{2} (x + 1) = 2

Add

lo g_{2} (x + 1)

to both sides

lo g_{2} (x) - lo g_{2} (x + 1) + lo g_{2} (x + 1) = 2 + lo g_{2} (x + 1)

Simplify

lo g_{2} (x) = 2 + lo g_{2} (x + 1)

Apply log rules

x = 4 (x + 1)

Solve

x = 4 (x + 1) : x = - \frac{4}{3}

x = - \frac{4}{3}

Verify Solutions:

x = - \frac{4}{3}

False

The solution is

No Solution for x \in R

lo g_{2} (x + 5) = 2 + lo g_{2} (x + 8)

2 lo g_{3} (x) = 2 + lo g_{3} (x - 2)

ln (4 + a e^{b t}) = 0

ln (x + 5) = ln (x - 1) + ln (x + 1)

- 3 = 20 lo g_{10} (\frac{1}{x})

What is the answer to log_{2}(x)-log_{2}(x+1)=2 ?
The answer to log_{2}(x)-log_{2}(x+1)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(x)-log_{2}(x+1)=2
The solution is No Solution for x\in\mathbb{R}