What is the answer to log_{2}(x+5)=2+log_{2}(x+8) ?

The answer to log_{2}(x+5)=2+log_{2}(x+8) is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(x+5)=2+log_{2}(x+8)

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (x + 5) = 2 + lo g_{2} (x + 8)

No Solution for x \in R

Solution steps

lo g_{2} (x + 5) = 2 + lo g_{2} (x + 8)

Apply log rules

x + 5 = 4 (x + 8)

Solve

x + 5 = 4 (x + 8) : x = - 9

x = - 9

Verify Solutions:

x = - 9

False

The solution is

No Solution for x \in R

2 lo g_{3} (x) = 2 + lo g_{3} (x - 2)

ln (4 + a e^{b t}) = 0

ln (x + 5) = ln (x - 1) + ln (x + 1)

- 3 = 20 lo g_{10} (\frac{1}{x})

lo g_{2} (x^{2} + 3 x - 2) = 1

What is the answer to log_{2}(x+5)=2+log_{2}(x+8) ?
The answer to log_{2}(x+5)=2+log_{2}(x+8) is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(x+5)=2+log_{2}(x+8)
The solution is No Solution for x\in\mathbb{R}