What is the answer to 4=(ln(4x))/(ln(2x)) ?

The answer to 4=(ln(4x))/(ln(2x)) is x= 1/(e^{\frac{2ln(2)){3}}}

Solve for x: 4=(ln(4x))/(ln(2x))

The solution is x= 1/(e^{\frac{2ln(2)){3}}}

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4 = \frac{ln ( 4 x )}{ln ( 2 x )}

x = \frac{1}{e ^{\frac{2 l n ( 2 )}{3}}}

Decimal Notation

x = 0.62996 \dots

Solution steps

4 = \frac{ln ( 4 x )}{ln ( 2 x )}

Multiply both sides by

ln (2 x)

4 ln (2 x) = \frac{ln ( 4 x )}{ln ( 2 x )} ln (2 x)

Simplify

4 ln (2 x) = ln (4 x)

Apply log rules

x = \frac{1}{e ^{\frac{2 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{2 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{2 l n ( 2 )}{3}}}

2 lo g_{2} (x) = x

lo g_{10} (3 + x) = lo g_{10} (x) + 2

lo g_{2} (z + 6) = lo g_{2} (z - 1) + 3

0.5075 = - lo g_{10} (x)

lo g_{3} (x - 5) = - 2

What is the answer to 4=(ln(4x))/(ln(2x)) ?
The answer to 4=(ln(4x))/(ln(2x)) is x= 1/(e^{\frac{2ln(2)){3}}}
Solve for x: 4=(ln(4x))/(ln(2x))
The solution is x= 1/(e^{\frac{2ln(2)){3}}}