What is the answer to log_{10}(3+x)=log_{10}(x)+2 ?

The answer to log_{10}(3+x)=log_{10}(x)+2 is x= 1/33

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log_{10}(3+x)=log_{10}(x)+2

lo g_{10} (3 + x) = lo g_{10} (x) + 2

x = \frac{1}{33}

Solution steps

lo g_{10} (3 + x) = lo g_{10} (x) + 2

Apply log rules

3 + x = x \cdot 100

Solve

3 + x = x \cdot 100 : x = \frac{1}{33}

x = \frac{1}{33}

Verify Solutions:

x = \frac{1}{33}

True

The solution is

x = \frac{1}{33}

lo g_{2} (z + 6) = lo g_{2} (z - 1) + 3

0.5075 = - lo g_{10} (x)

lo g_{3} (x - 5) = - 2

- 1 = ln (7 x)

ln (x^{2}) - ln (5) = 4

What is the answer to log_{10}(3+x)=log_{10}(x)+2 ?
The answer to log_{10}(3+x)=log_{10}(x)+2 is x= 1/33
Solve for x: log_{10}(3+x)=log_{10}(x)+2
The solution is x= 1/33