What is the answer to log_{10}(3x)=-log_{10}(9) ?

The answer to log_{10}(3x)=-log_{10}(9) is x= 1/27

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log_{10}(3x)=-log_{10}(9)

lo g_{10} (3 x) = - lo g_{10} (9)

x = \frac{1}{27}

Solution steps

lo g_{10} (3 x) = - lo g_{10} (9)

Apply log rules

3 x = \frac{1}{9}

Solve

3 x = \frac{1}{9} : x = \frac{1}{27}

x = \frac{1}{27}

2 lo g_{10} (x) - 2 lo g_{10} (2) = 1

lo g_{2} (n) = 2147483648

2 ln (x - 4) + ln (x + 9) = 3 ln (x)

\frac{x + n}{2 ln ( x ) - n} = 0

lo g_{3} (9 x) + lo g_{3} (8) = 5

What is the answer to log_{10}(3x)=-log_{10}(9) ?
The answer to log_{10}(3x)=-log_{10}(9) is x= 1/27
Solve for x: log_{10}(3x)=-log_{10}(9)
The solution is x= 1/27