What is the answer to 2log_{10}(x)-2log_{10}(2)=1 ?

The answer to 2log_{10}(x)-2log_{10}(2)=1 is x=10^{(1+2log_{10}(2))/2}

Solve for x: 2log_{10}(x)-2log_{10}(2)=1

The solution is x=10^{(1+2log_{10}(2))/2}

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2 lo g_{10} (x) - 2 lo g_{10} (2) = 1

x = 1 0^{\frac{1 + 2 l o g _{10} ( 2 )}{2}}

Solution steps

2 lo g_{10} (x) - 2 lo g_{10} (2) = 1

Move

2 lo g_{10} (2)

to the right side

2 lo g_{10} (x) = 1 + 2 lo g_{10} (2)

Divide both sides by

2

lo g_{10} (x) = \frac{1 + 2 lo g _{10} ( 2 )}{2}

Apply log rules

x = 1 0^{\frac{1 + 2 l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{1 + 2 l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{1 + 2 l o g _{10} ( 2 )}{2}}

lo g_{2} (n) = 2147483648

2 ln (x - 4) + ln (x + 9) = 3 ln (x)

\frac{x + n}{2 ln ( x ) - n} = 0

lo g_{3} (9 x) + lo g_{3} (8) = 5

lo g_{6} (x + 7) + lo g_{6} (x + 4) = 2

What is the answer to 2log_{10}(x)-2log_{10}(2)=1 ?
The answer to 2log_{10}(x)-2log_{10}(2)=1 is x=10^{(1+2log_{10}(2))/2}
Solve for x: 2log_{10}(x)-2log_{10}(2)=1
The solution is x=10^{(1+2log_{10}(2))/2}