What is the answer to 2log_{10}(x)=-3log_{10}(2) ?

The answer to 2log_{10}(x)=-3log_{10}(2) is x= 1/(10^{(3log_{10)(2))/2}}

Solve for x: 2log_{10}(x)=-3log_{10}(2)

The solution is x= 1/(10^{(3log_{10)(2))/2}}

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2 lo g_{10} (x) = - 3 lo g_{10} (2)

x = \frac{1}{1 0 ^{\frac{3 l o g _{10} ( 2 )}{2}}}

Decimal Notation

x = 0.35355 \dots

Solution steps

2 lo g_{10} (x) = - 3 lo g_{10} (2)

Divide both sides by

2

lo g_{10} (x) = - \frac{3 lo g _{10} ( 2 )}{2}

Apply log rules

x = \frac{1}{1 0 ^{\frac{3 l o g _{10} ( 2 )}{2}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{3 l o g _{10} ( 2 )}{2}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{3 l o g _{10} ( 2 )}{2}}}

20 = 3 lo g_{2} (1 + \frac{s}{n})

ln (\frac{t - 65}{125}) = - 0.07 t

lo g_{a} (x) = lo g_{a} (x)

y, ln (y) = 4 ln (x) + c

lo g_{10} ((x + 2) (x - 1)) = 1

What is the answer to 2log_{10}(x)=-3log_{10}(2) ?
The answer to 2log_{10}(x)=-3log_{10}(2) is x= 1/(10^{(3log_{10)(2))/2}}
Solve for x: 2log_{10}(x)=-3log_{10}(2)
The solution is x= 1/(10^{(3log_{10)(2))/2}}