What is the answer to solvefor y,ln(y)=4ln(x)+c ?

The answer to solvefor y,ln(y)=4ln(x)+c is y=e^cx^4

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solvefor y,ln(y)=4ln(x)+c

solve for

y, ln (y) = 4 ln (x) + c

y = e^{c} x^{4}

Solution steps

ln (y) = 4 ln (x) + c

Apply log rules

y = e^{c} x^{4}

lo g_{10} ((x + 2) (x - 1)) = 1

1.73 = - lo g_{10} (x)

10 0^{l o g_{10} (x)} = 2 x^{2}

x^{l o g_{10} (x^{2}) + 1} = x^{3}

lo g_{6} (x) - lo g_{6} (x - 1) = 2

What is the answer to solvefor y,ln(y)=4ln(x)+c ?
The answer to solvefor y,ln(y)=4ln(x)+c is y=e^cx^4