What is the answer to 3+log_{2}(2x)=log_{2}(17x-5) ?

The answer to 3+log_{2}(2x)=log_{2}(17x-5) is x=5

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3+log_{2}(2x)=log_{2}(17x-5)

3 + lo g_{2} (2 x) = lo g_{2} (17 x - 5)

x = 5

Solution steps

3 + lo g_{2} (2 x) = lo g_{2} (17 x - 5)

Apply log rules

16 x = 17 x - 5

Solve

16 x = 17 x - 5 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

ln (x - 4) - ln (x) = 5

x, ln (y) = 2 ln (x) + 2 c

lo g_{2 - x} (2 x^{2} - 1) = 2

lo g_{e} (x - 2) - 3 lo g_{e} (2) = 2

ln (x + 5) - ln (x - 4) = ln (x)

What is the answer to 3+log_{2}(2x)=log_{2}(17x-5) ?
The answer to 3+log_{2}(2x)=log_{2}(17x-5) is x=5
Solve for x: 3+log_{2}(2x)=log_{2}(17x-5)
The solution is x=5