What is the answer to 6+7*log_{2}(x)=21 ?

The answer to 6+7*log_{2}(x)=21 is x=4\sqrt[7]{2}

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6+7*log_{2}(x)=21

6 + 7 \cdot lo g_{2} (x) = 21

Solution steps

6 + 7 lo g_{2} (x) = 21

Move

6

to the right side

7 lo g_{2} (x) = 15

Divide both sides by

7

lo g_{2} (x) = \frac{15}{7}

Apply log rules

Verify Solutions:

True

The solution is

lo g_{3} (2 x - 3) + lo g_{3} (x + 3) = 4

lo g_{2} (x + 6) = 2 + lo g_{2} (x + 3)

lo g_{4} (x + 9) = 2

17 = 10 lo g_{a} (x)

lo g_{4} (x) = \frac{25}{10}

What is the answer to 6+7*log_{2}(x)=21 ?
The answer to 6+7*log_{2}(x)=21 is x=4\sqrt[7]{2}
Solve for x: 6+7*log_{2}(x)=21
The solution is x=4\sqrt[7]{2}