What is the answer to log_{2}(x+6)=2+log_{2}(x+3) ?

The answer to log_{2}(x+6)=2+log_{2}(x+3) is x=-2

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log_{2}(x+6)=2+log_{2}(x+3)

lo g_{2} (x + 6) = 2 + lo g_{2} (x + 3)

x = - 2

Solution steps

lo g_{2} (x + 6) = 2 + lo g_{2} (x + 3)

Apply log rules

x + 6 = 4 (x + 3)

Solve

x + 6 = 4 (x + 3) : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

lo g_{4} (x + 9) = 2

17 = 10 lo g_{a} (x)

lo g_{4} (x) = \frac{25}{10}

2 ln (x + 4) - ln (x) = ln (x + a)

ln (3.5 x + 1.1) - 1.2 = 16.7

What is the answer to log_{2}(x+6)=2+log_{2}(x+3) ?
The answer to log_{2}(x+6)=2+log_{2}(x+3) is x=-2
Solve for x: log_{2}(x+6)=2+log_{2}(x+3)
The solution is x=-2