What is the answer to 2log_{2}(y)+log_{4}(y)=9 ?

The answer to 2log_{2}(y)+log_{4}(y)=9 is y=4*4^{4/5}

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2log_{2}(y)+log_{4}(y)=9

2 lo g_{2} (y) + lo g_{4} (y) = 9

y = 4 \cdot 4^{\frac{4}{5}}

Decimal Notation

y = 12.12573 \dots

Solution steps

2 lo g_{2} (y) + lo g_{4} (y) = 9

Apply log rules

y = 4 \cdot 4^{\frac{4}{5}}

Verify Solutions:

y = 4 \cdot 4^{\frac{4}{5}}

True

The solution is

y = 4 \cdot 4^{\frac{4}{5}}

x - 1 = lo g_{2} (3^{x})

y, lo g_{5} (y) = x

lo g_{6} (x + 1) = 2 - lo g_{6} (2)

2 lo g_{3} (4 x + 1) = 4

ln (x + 2) + \frac{x}{x + 2} = 0

What is the answer to 2log_{2}(y)+log_{4}(y)=9 ?
The answer to 2log_{2}(y)+log_{4}(y)=9 is y=4*4^{4/5}
Solve for y: 2log_{2}(y)+log_{4}(y)=9
The solution is y=4*4^{4/5}