What is the answer to 2.4=-log_{10}(x) ?

The answer to 2.4=-log_{10}(x) is x= 1/(10^{2.4)}

Solve for x: 2.4=-log_{10}(x)

The solution is x= 1/(10^{2.4)}

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2.4 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{2.4}}

Decimal Notation

x = 0.00398 \dots

Solution steps

2.4 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

2.4 + lo g_{10} (x) = 0

Move

2.4

to the right side

lo g_{10} (x) = - 2.4

Apply log rules

x = \frac{1}{1 0 ^{2.4}}

Verify Solutions:

x = \frac{1}{1 0 ^{2.4}}

True

The solution is

x = \frac{1}{1 0 ^{2.4}}

ln ((x - 3)^{4}) = 8

lo g_{2} (x + 4) + lo g_{2} (x - 2) = 4

ln (7 x + e) = 7

lo g_{x} (x^{2} - 2 x - 1) = 2

ln (x) = 1.2

What is the answer to 2.4=-log_{10}(x) ?
The answer to 2.4=-log_{10}(x) is x= 1/(10^{2.4)}
Solve for x: 2.4=-log_{10}(x)
The solution is x= 1/(10^{2.4)}