What is the answer to log_{6}(x+1)+log_{6}(x)=1 ?

The answer to log_{6}(x+1)+log_{6}(x)=1 is x=2

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log_{6}(x+1)+log_{6}(x)=1

lo g_{6} (x + 1) + lo g_{6} (x) = 1

x = 2

Solution steps

lo g_{6} (x + 1) + lo g_{6} (x) = 1

Apply log rules

(x + 1) x = 6

Solve

(x + 1) x = 6 : x = 2, x = - 3

x = 2, x = - 3

Verify Solutions:

x = 2

True

, x = - 3

False

The solution is

x = 2

lo g_{2} (x) = (lo g_{2} (x))^{2}

8 ln (x - 9) = 1

lo g_{3} (x) = lo g_{9} (2 x - 1)

ln (x + 7) + ln (x - 4) = 2 ln (x)

lo g_{10} (x) = 0.00002

What is the answer to log_{6}(x+1)+log_{6}(x)=1 ?
The answer to log_{6}(x+1)+log_{6}(x)=1 is x=2
Solve for x: log_{6}(x+1)+log_{6}(x)=1
The solution is x=2