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Popular >

2x+2*ln(x+1)+D=2

Solution

2 x + 2 \cdot ln (x + 1) + D = 2

Solution

x = W (\frac{1}{e ^{\frac{D - 4}{2}}}) - 1

Solution steps

2 x + 2 ln (x + 1) + D = 2

Move

2 x

to the right side

2 ln (x + 1) + D = 2 - 2 x

Move

D

to the right side

2 ln (x + 1) = 2 - 2 x - D

Divide both sides by

2

ln (x + 1) = \frac{2 - 2 x - D}{2}

If

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + 1)} = e^{\frac{2 - 2 x - D}{2}}

Simplify

e^{l n (x + 1)} : x + 1

x + 1 = e^{\frac{2 - 2 x - D}{2}}

Solve

x + 1 = e^{\frac{2 - 2 x - D}{2}} : x = W (\frac{1}{e ^{\frac{D - 4}{2}}}) - 1

x = W (\frac{1}{e ^{\frac{D - 4}{2}}}) - 1

Verify Solutions:

x = W (\frac{1}{e ^{\frac{D - 4}{2}}}) - 1

True

The solution is

x = W (\frac{1}{e ^{\frac{D - 4}{2}}}) - 1

Popular Examples

log_{3}(x+1)-log_{3}(x)=3

lo g_{3} (x + 1) - lo g_{3} (x) = 3

log_{6}(x+1)+log_{6}(x)=1

lo g_{6} (x + 1) + lo g_{6} (x) = 1

log_{2}(x)=(log_{2}(x))^2

lo g_{2} (x) = (lo g_{2} (x))^{2}

8 ln (x - 9) = 1

log_{3}(x)=log_{9}(2x-1)

lo g_{3} (x) = lo g_{9} (2 x - 1)

Frequently Asked Questions (FAQ)

What is the answer to 2x+2*ln(x+1)+D=2 ?
The answer to 2x+2*ln(x+1)+D=2 is x=\W(1/(e^{\frac{D-4){2}}})-1