What is the answer to log_{3}(x)=log_{9}(2x-1) ?

The answer to log_{3}(x)=log_{9}(2x-1) is x=1

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log_{3}(x)=log_{9}(2x-1)

lo g_{3} (x) = lo g_{9} (2 x - 1)

x = 1

Solution steps

lo g_{3} (x) = lo g_{9} (2 x - 1)

Apply log rules

x^{2} = 2 x - 1

Solve

x^{2} = 2 x - 1 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

ln (x + 7) + ln (x - 4) = 2 ln (x)

lo g_{10} (x) = 0.00002

lo g_{5} (x) = 3 - lo g_{5} (x + 20)

2 - 2.12 = lo g_{10} (x)

- 35.5 = 10 lo g_{10} (\frac{x}{1})

What is the answer to log_{3}(x)=log_{9}(2x-1) ?
The answer to log_{3}(x)=log_{9}(2x-1) is x=1
Solve for x: log_{3}(x)=log_{9}(2x-1)
The solution is x=1