What is the answer to -6=20log_{10}(0.5-0.62x) ?

The answer to -6=20log_{10}(0.5-0.62x) is x=-(5(10^{7/10}-5))/(31)

Solve for x: -6=20log_{10}(0.5-0.62x)

The solution is x=-(5(10^{7/10}-5))/(31)

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- 6 = 20 lo g_{10} (0.5 - 0.62 x)

x = - \frac{5 ( 1 0 ^{\frac{7}{10}} - 5 )}{31}

Decimal Notation

x = - 0.00191 \dots

Solution steps

- 6 = 20 lo g_{10} (0.5 - 0.62 x)

Switch sides

20 lo g_{10} (0.5 - 0.62 x) = - 6

Divide both sides by

20

lo g_{10} (0.5 - 0.62 x) = - \frac{3}{10}

Apply log rules

0.5 - 0.62 x = \frac{1}{1 0 ^{\frac{3}{10}}}

Solve

0.5 - 0.62 x = \frac{1}{1 0 ^{\frac{3}{10}}} : x = - \frac{5 ( 1 0 ^{\frac{7}{10}} - 5 )}{31}

x = - \frac{5 ( 1 0 ^{\frac{7}{10}} - 5 )}{31}

Verify Solutions:

x = - \frac{5 ( 1 0 ^{\frac{7}{10}} - 5 )}{31}

True

The solution is

x = - \frac{5 ( 1 0 ^{\frac{7}{10}} - 5 )}{31}

x, lo g_{3} (x) = - 3

lo g_{2} (x + 5) + lo g_{2} (4 x + 4) = 7

x^{(2 l o g_{9} (x)) - 1} = 3 x

lo g_{2} (x^{2} + 2 x - 2) = 0

lo g_{4} (2 x + 6) = 2

What is the answer to -6=20log_{10}(0.5-0.62x) ?
The answer to -6=20log_{10}(0.5-0.62x) is x=-(5(10^{7/10}-5))/(31)
Solve for x: -6=20log_{10}(0.5-0.62x)
The solution is x=-(5(10^{7/10}-5))/(31)