What is the answer to solvefor x,ln(x)-ln(2x+1)=1 ?

The answer to solvefor x,ln(x)-ln(2x+1)=1 is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(x)-ln(2x+1)=1

solve for

x, ln (x) - ln (2 x + 1) = 1

No Solution for x \in R

Solution steps

ln (x) - ln (2 x + 1) = 1

Add

ln (2 x + 1)

to both sides

ln (x) - ln (2 x + 1) + ln (2 x + 1) = 1 + ln (2 x + 1)

Simplify

ln (x) = 1 + ln (2 x + 1)

Apply log rules

x = e (2 x + 1)

Solve

x = e (2 x + 1) : x = \frac{e}{1 - 2 e}

x = \frac{e}{1 - 2 e}

Verify Solutions:

x = \frac{e}{1 - 2 e}

False

The solution is

No Solution for x \in R

20 \cdot lo g_{10} (x) = - 20

lo g_{2} (x - 2) + lo g_{2} (x - 4) = 3

lo g_{y} (2) - lo g_{4} (y) = 1

lo g_{4} (1 + x^{2}) = - 0.25

lo g_{10} (y) = - 138.265

What is the answer to solvefor x,ln(x)-ln(2x+1)=1 ?
The answer to solvefor x,ln(x)-ln(2x+1)=1 is No Solution for x\in\mathbb{R}