What is the answer to log_{3}(x)-log_{3}(x+6)=-1 ?

The answer to log_{3}(x)-log_{3}(x+6)=-1 is x=3

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log_{3}(x)-log_{3}(x+6)=-1

lo g_{3} (x) - lo g_{3} (x + 6) = - 1

x = 3

Solution steps

lo g_{3} (x) - lo g_{3} (x + 6) = - 1

Add

lo g_{3} (x + 6)

to both sides

lo g_{3} (x) - lo g_{3} (x + 6) + lo g_{3} (x + 6) = - 1 + lo g_{3} (x + 6)

Simplify

lo g_{3} (x) = - 1 + lo g_{3} (x + 6)

Apply log rules

x \cdot 3 = x + 6

Solve

x \cdot 3 = x + 6 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

0 = ln (ln (x))

ln (X) = - 4423 (0.00352) + 3.665

lo g_{4} (4 x^{2}) - lo g_{4} (9) = 3

lo g_{\frac{1}{2}} (x) = 99500

lo g_{6} (x^{6}) = 1

What is the answer to log_{3}(x)-log_{3}(x+6)=-1 ?
The answer to log_{3}(x)-log_{3}(x+6)=-1 is x=3
Solve for x: log_{3}(x)-log_{3}(x+6)=-1
The solution is x=3