What is the answer to ln(15)=ln^5(+ln(x+1)) ?

The answer to ln(15)=ln^5(+ln(x+1)) is x=e^{e^{\sqrt[5]{ln(15)}}}-1

Solve for x: ln(15)=ln^5(+ln(x+1))

The solution is x=e^{e^{\sqrt[5]{ln(15)}}}-1

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ln (15) = ln^{5} (+ ln (x + 1))

Decimal Notation

x = 28.63097 \dots

Solution steps

ln (15) = ln^{5} (ln (x + 1))

Rewrite the equation with

ln (ln (x + 1)) = u

ln (15) = u^{5}

Solve

Substitute back

u = ln (ln (x + 1)),

solve for

x

Solve

Verify Solutions:

True

The solution is

lo g_{2} (14 - 5 x) = 2

lo g_{x} (\frac{16}{81}) = - 4

2 \cdot ln (x) - ln (2) = ln (2 x - 1)

lo g_{3} (4 x - 5) = lo g_{3} (x + 3)

20 lo g_{10} (x) = 29.5

What is the answer to ln(15)=ln^5(+ln(x+1)) ?
The answer to ln(15)=ln^5(+ln(x+1)) is x=e^{e^{\sqrt[5]{ln(15)}}}-1
Solve for x: ln(15)=ln^5(+ln(x+1))
The solution is x=e^{e^{\sqrt[5]{ln(15)}}}-1