What is the answer to ln(4x+1)-ln(3x-2)=ln(5) ?

The answer to ln(4x+1)-ln(3x-2)=ln(5) is x=1

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ln(4x+1)-ln(3x-2)=ln(5)

ln (4 x + 1) - ln (3 x - 2) = ln (5)

x = 1

Solution steps

ln (4 x + 1) - ln (3 x - 2) = ln (5)

Add

ln (3 x - 2)

to both sides

ln (4 x + 1) - ln (3 x - 2) + ln (3 x - 2) = ln (5) + ln (3 x - 2)

Simplify

ln (4 x + 1) = ln (5) + ln (3 x - 2)

Apply log rules

4 x + 1 = 5 (3 x - 2)

Solve

4 x + 1 = 5 (3 x - 2) : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

- 1.8 = lo g_{10} (x)

lo g_{2} (10 x - x^{2}) = 4

lo g_{10} (4) + lo g_{10} (- 5 x) = 2

lo g_{100} (x) = 0.05

lo g_{4} (9 x) - lo g_{4} (3) = 0

What is the answer to ln(4x+1)-ln(3x-2)=ln(5) ?
The answer to ln(4x+1)-ln(3x-2)=ln(5) is x=1
Solve for x: ln(4x+1)-ln(3x-2)=ln(5)
The solution is x=1