What is the answer to log_{4}(9x)-log_{4}(3)=0 ?

The answer to log_{4}(9x)-log_{4}(3)=0 is x= 1/3

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log_{4}(9x)-log_{4}(3)=0

lo g_{4} (9 x) - lo g_{4} (3) = 0

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

lo g_{4} (9 x) - lo g_{4} (3) = 0

Move

lo g_{4} (3)

to the right side

lo g_{4} (9 x) = lo g_{4} (3)

Apply log rules

9 x = 3

Solve

9 x = 3 : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

lo g_{3} (5) + lo g_{3} (X - 6) = 2

lo g_{10} (x) = 15.2

3^{2} = [lo g_{3} (x + 5)]^{3}

ln (x e^{x}) = ln (5 e^{x} - 5)

ln (x) = 3 - 2 x

What is the answer to log_{4}(9x)-log_{4}(3)=0 ?
The answer to log_{4}(9x)-log_{4}(3)=0 is x= 1/3
Solve for x: log_{4}(9x)-log_{4}(3)=0
The solution is x= 1/3