What is the answer to log_{10}(4)+log_{10}(-5x)=2 ?

The answer to log_{10}(4)+log_{10}(-5x)=2 is x=-5

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log_{10}(4)+log_{10}(-5x)=2

lo g_{10} (4) + lo g_{10} (- 5 x) = 2

x = - 5

Solution steps

lo g_{10} (4) + lo g_{10} (- 5 x) = 2

Move

lo g_{10} (4)

to the right side

lo g_{10} (- 5 x) = 2 - lo g_{10} (4)

Apply log rules

- 5 x = 25

Solve

- 5 x = 25 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

lo g_{100} (x) = 0.05

lo g_{4} (9 x) - lo g_{4} (3) = 0

lo g_{3} (5) + lo g_{3} (X - 6) = 2

lo g_{10} (x) = 15.2

3^{2} = [lo g_{3} (x + 5)]^{3}

What is the answer to log_{10}(4)+log_{10}(-5x)=2 ?
The answer to log_{10}(4)+log_{10}(-5x)=2 is x=-5
Solve for x: log_{10}(4)+log_{10}(-5x)=2
The solution is x=-5