What is the answer to log_{10}(2x-2)=-1 ?

The answer to log_{10}(2x-2)=-1 is x= 21/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(2x-2)=-1

lo g_{10} (2 x - 2) = - 1

x = \frac{21}{20}

Decimal Notation

x = 1.05

Solution steps

lo g_{10} (2 x - 2) = - 1

Apply log rules

2 x - 2 = \frac{1}{10}

Solve

2 x - 2 = \frac{1}{10} : x = \frac{21}{20}

x = \frac{21}{20}

lo g_{3} (x + 25) + lo g_{3} (x - 1) = 3

lo g_{10} (x^{2} - x) = 0

ln (2) = ln (1 (0 - 1) + c)

ln (\frac{2}{5 x}) = ln (5)

4 lo g_{3} (4 x - 12) = 8

What is the answer to log_{10}(2x-2)=-1 ?
The answer to log_{10}(2x-2)=-1 is x= 21/20
Solve for x: log_{10}(2x-2)=-1
The solution is x= 21/20