What is the answer to log_{10}(x^2-x)=0 ?

The answer to log_{10}(x^2-x)=0 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Solve for x: log_{10}(x^2-x)=0

The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

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lo g_{10} (x^{2} - x) = 0

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Decimal Notation

x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

lo g_{10} (x^{2} - x) = 0

Apply log rules

x^{2} - x = 1

Solve

x^{2} - x = 1 : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

ln (2) = ln (1 (0 - 1) + c)

ln (\frac{2}{5 x}) = ln (5)

4 lo g_{3} (4 x - 12) = 8

x, - 4 ln (2 x) = - 2.773

lo g_{10} (5) (2 x + 3) = lo g_{8} (x)

What is the answer to log_{10}(x^2-x)=0 ?
The answer to log_{10}(x^2-x)=0 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Solve for x: log_{10}(x^2-x)=0
The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2