What is the answer to log_{10}(sqrt(x^320000))=2 ?

The answer to log_{10}(sqrt(x^320000))=2 is x= 1/(\sqrt[3]{2)}

Solve for x: log_{10}(sqrt(x^320000))=2

The solution is x= 1/(\sqrt[3]{2)}

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lo g_{10} (x^{3} 20000) = 2

Decimal Notation

x = 0.79370 \dots

Solution steps

lo g_{10} (x^{3} \cdot 20000) = 2

Apply log rules

1002 x x^{2} = 100

Solve

lo g_{7} (x) = 9 lo g_{x} (7)

lo g_{10} (x^{2} + 2 x - 8) = 0

x^{2} = 2 x^{2} ln (x)

- ln (2 + x) = 2

ln (x^{2} + 2 x) = ln (x)

What is the answer to log_{10}(sqrt(x^320000))=2 ?
The answer to log_{10}(sqrt(x^320000))=2 is x= 1/(\sqrt[3]{2)}
Solve for x: log_{10}(sqrt(x^320000))=2
The solution is x= 1/(\sqrt[3]{2)}