What is the answer to log_{2}(x+2)=log_{2}(7x) ?

The answer to log_{2}(x+2)=log_{2}(7x) is x= 1/3

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log_{2}(x+2)=log_{2}(7x)

lo g_{2} (x + 2) = lo g_{2} (7 x)

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

lo g_{2} (x + 2) = lo g_{2} (7 x)

Apply log rules

x + 2 = 7 x

Solve

x + 2 = 7 x : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

lo g_{10} (x) = - 2 + lo g_{2} (x)

q, p = 8 - lo g_{3} (q)

lo g_{10} (t^{2} - 2) = 4

ln (x) + ln (8 x) = 9

20 \cdot lo g_{10} (X) = 20

What is the answer to log_{2}(x+2)=log_{2}(7x) ?
The answer to log_{2}(x+2)=log_{2}(7x) is x= 1/3
Solve for x: log_{2}(x+2)=log_{2}(7x)
The solution is x= 1/3