What is the answer to log_{10}(t^2-2)=4 ?

The answer to log_{10}(t^2-2)=4 is t=sqrt(10002),t=-sqrt(10002)

Solve for t: log_{10}(t^2-2)=4

The solution is t=sqrt(10002),t=-sqrt(10002)

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lo g_{10} (t^{2} - 2) = 4

t = 10002, t = - 10002

Decimal Notation

t = 100.00999 \dots, t = - 100.00999 \dots

Solution steps

lo g_{10} (t^{2} - 2) = 4

Apply log rules

t^{2} - 2 = 10000

Solve

t^{2} - 2 = 10000 : t = 10002, t = - 10002

t = 10002, t = - 10002

ln (x) + ln (8 x) = 9

20 \cdot lo g_{10} (X) = 20

lo g_{10} (2 x) = 1.6

lo g_{2} (2 x + 2) = 0

lo g_{2} (2 x + 2) = 1

What is the answer to log_{10}(t^2-2)=4 ?
The answer to log_{10}(t^2-2)=4 is t=sqrt(10002),t=-sqrt(10002)
Solve for t: log_{10}(t^2-2)=4
The solution is t=sqrt(10002),t=-sqrt(10002)