What is the answer to log_{10}(x)=-2+log_{2}(x) ?

The answer to log_{10}(x)=-2+log_{2}(x) is x= 1/(10^{(2log_{10)(2))/(log_{10)(2)-1}}}

Solve for x: log_{10}(x)=-2+log_{2}(x)

The solution is x= 1/(10^{(2log_{10)(2))/(log_{10)(2)-1}}}

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lo g_{10} (x) = - 2 + lo g_{2} (x)

x = \frac{1}{1 0 ^{\frac{2 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

Decimal Notation

x = 7.26696 \dots

Solution steps

lo g_{10} (x) = - 2 + lo g_{2} (x)

Apply log rules

x = \frac{1}{1 0 ^{\frac{2 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{2 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{2 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

q, p = 8 - lo g_{3} (q)

lo g_{10} (t^{2} - 2) = 4

ln (x) + ln (8 x) = 9

20 \cdot lo g_{10} (X) = 20

lo g_{10} (2 x) = 1.6

What is the answer to log_{10}(x)=-2+log_{2}(x) ?
The answer to log_{10}(x)=-2+log_{2}(x) is x= 1/(10^{(2log_{10)(2))/(log_{10)(2)-1}}}
Solve for x: log_{10}(x)=-2+log_{2}(x)
The solution is x= 1/(10^{(2log_{10)(2))/(log_{10)(2)-1}}}