What is the answer to log_{10}(2x)=1.6 ?

The answer to log_{10}(2x)=1.6 is x=(10^{1.6})/2

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log_{10}(2x)=1.6

lo g_{10} (2 x) = 1.6

x = \frac{1 0 ^{1.6}}{2}

Decimal Notation

x = 19.90535 \dots

Solution steps

lo g_{10} (2 x) = 1.6

Apply log rules

2 x = 1 0^{1.6}

Solve

2 x = 1 0^{1.6} : x = \frac{1 0 ^{1.6}}{2}

x = \frac{1 0 ^{1.6}}{2}

lo g_{2} (2 x + 2) = 0

lo g_{2} (2 x + 2) = 1

lo g_{4} (x + 6) + lo g_{4} (x) = 2

(x + 12) = ln (x) + ln (12)

lo g_{3} (3) + lo g_{3} (x) = 10

What is the answer to log_{10}(2x)=1.6 ?
The answer to log_{10}(2x)=1.6 is x=(10^{1.6})/2
Solve for x: log_{10}(2x)=1.6
The solution is x=(10^{1.6})/2