What is the answer to log_{6}(p+2)+log_{6}(p+7)=2 ?

The answer to log_{6}(p+2)+log_{6}(p+7)=2 is p=2

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log_{6}(p+2)+log_{6}(p+7)=2

lo g_{6} (p + 2) + lo g_{6} (p + 7) = 2

p = 2

Solution steps

lo g_{6} (p + 2) + lo g_{6} (p + 7) = 2

Apply log rules

(p + 2) (p + 7) = 36

Solve

(p + 2) (p + 7) = 36 : p = 2, p = - 11

p = 2, p = - 11

Verify Solutions:

p = 2

True

, p = - 11

False

The solution is

p = 2

8 ln (2 x) = 48

lo g_{3} ((x + 2)^{2}) = 2

ln (3) + ln (x - 1) = 1

lo g_{10} (1 - d) = - 0.19

3 lo g_{4} (4 x) = 6

What is the answer to log_{6}(p+2)+log_{6}(p+7)=2 ?
The answer to log_{6}(p+2)+log_{6}(p+7)=2 is p=2
Solve for p: log_{6}(p+2)+log_{6}(p+7)=2
The solution is p=2