What is the answer to ln(3)+ln(x-1)=1 ?

The answer to ln(3)+ln(x-1)=1 is x= e/3+1

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ln(3)+ln(x-1)=1

ln (3) + ln (x - 1) = 1

x = \frac{e}{3} + 1

Decimal

x = 1.90609 \dots

Solution steps

ln (3) + ln (x - 1) = 1

Move

ln (3)

to the right side

ln (x - 1) = 1 - ln (3)

Apply log rules

x - 1 = \frac{e}{3}

Solve

x - 1 = \frac{e}{3} : x = \frac{e}{3} + 1

x = \frac{e}{3} + 1

Verify Solutions:

x = \frac{e}{3} + 1

True

The solution is

x = \frac{e}{3} + 1

lo g_{10} (1 - d) = - 0.19

3 lo g_{4} (4 x) = 6

y, 2 ln (y + 2) = 2 x^{2} + C

x 6 - 5 ln (x) = 2

ln (3 x) = 3 ln (x)

What is the answer to ln(3)+ln(x-1)=1 ?
The answer to ln(3)+ln(x-1)=1 is x= e/3+1
Solve for x: ln(3)+ln(x-1)=1
The solution is x= e/3+1