What is the answer to (1-ln(2x))/(x^2)=0 ?

The answer to (1-ln(2x))/(x^2)=0 is x= e/2

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(1-ln(2x))/(x^2)=0

\frac{1 - ln ( 2 x )}{x ^{2}} = 0

x = \frac{e}{2}

Decimal Notation

x = 1.35914 \dots

Solution steps

\frac{1 - ln ( 2 x )}{x ^{2}} = 0

Multiply both sides by

x^{2}

1 - ln (2 x) = 0

Move

1

to the right side

- ln (2 x) = - 1

Divide both sides by

- 1

ln (2 x) = 1

Apply log rules

2 x = e

Solve

2 x = e : x = \frac{e}{2}

x = \frac{e}{2}

Verify Solutions:

x = \frac{e}{2}

True

The solution is

x = \frac{e}{2}

lo g_{3} (5 x + 2) + lo g_{3} (6) = 5

lo g_{x} (10) = lo g_{10} (x)

lo g_{4} (- 8 - 4 x) = 1

ln (5 x) = 3

1 + 2 lo g_{3} (x) = lo g_{3} (28 x - 9)

What is the answer to (1-ln(2x))/(x^2)=0 ?
The answer to (1-ln(2x))/(x^2)=0 is x= e/2
Solve for x: (1-ln(2x))/(x^2)=0
The solution is x= e/2