What is the answer to solvefor x,-ln(y)=ln(x)+4 ?

The answer to solvefor x,-ln(y)=ln(x)+4 is x= 1/(e^4y) {y>0}

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solvefor x,-ln(y)=ln(x)+4

solve for

x, - ln (y) = ln (x) + 4

x = \frac{1}{e ^{4} y} {y > 0}

Solution steps

- ln (y) = ln (x) + 4

Switch sides

ln (x) + 4 = - ln (y)

Move

4

to the right side

ln (x) = - ln (y) - 4

Apply log rules

x = \frac{1}{e ^{4} y}

Verify Solutions:

x = \frac{1}{e ^{4} y} {y > 0}

The solution is

x = \frac{1}{e ^{4} y} {y > 0}

8 = lo g_{x} (256)

y = 4 \cdot ln (x + c), x

2 = - lo g_{10} (t)

7.3 = 20 lo g_{10} (\frac{4.7}{x})

- 30 = 10 \cdot lo g_{10} (w)

What is the answer to solvefor x,-ln(y)=ln(x)+4 ?
The answer to solvefor x,-ln(y)=ln(x)+4 is x= 1/(e^4y) {y>0}