What is the answer to solvefor x,ln(y)=ln(2x) ?

The answer to solvefor x,ln(y)=ln(2x) is x= y/2 {y>0}

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solvefor x,ln(y)=ln(2x)

solve for

x, ln (y) = ln (2 x)

x = \frac{y}{2} {y > 0}

Solution steps

ln (y) = ln (2 x)

Apply log rules

y = 2 x

Solve

y = 2 x : x = \frac{y}{2}

x = \frac{y}{2}

Verify Solutions:

x = \frac{y}{2} {y > 0}

The solution is

x = \frac{y}{2} {y > 0}

lo g_{4} (2 x + 1) = lo g_{4} (x - 4)

2.0028 = - ln (0.02 - x)

lo g_{a} (x) = lo g_{2} (1)

lo g_{3}^{2} (x) - 2 lo g_{3} (x) = 0

x, lo g_{b} (x) = y

What is the answer to solvefor x,ln(y)=ln(2x) ?
The answer to solvefor x,ln(y)=ln(2x) is x= y/2 {y>0}