What is the answer to solvefor y,x=3log_{y}(2) ?

The answer to solvefor y,x=3log_{y}(2) is y=2^{3/x} {x 0}

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solvefor y,x=3log_{y}(2)

solve for

y, x = 3 lo g_{y} (2)

y = 2^{\frac{3}{x}} {x < 0 or x > 0}

Solution steps

x = 3 lo g_{y} (2)

Switch sides

3 lo g_{y} (2) = x

Divide both sides by

3

lo g_{y} (2) = \frac{x}{3}

Apply log rules

\frac{1}{lo g _{2} ( y )} = \frac{x}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot 3 = lo g_{2} (y) x

Simplify

3 = lo g_{2} (y) x

Switch sides

lo g_{2} (y) x = 3

Divide both sides by

x

lo g_{2} (y) = \frac{3}{x}

Apply log rules

y = 2^{\frac{3}{x}}

Verify Solutions:

y = 2^{\frac{3}{x}} {x < 0 or x > 0}

The solution is

y = 2^{\frac{3}{x}} {x < 0 or x > 0}

b = ln (\frac{x}{a}), x

5 lo g_{32} (A - 7) = - 1

lo g_{x} (100) = 3

2 = lo g_{b} (49)

lo g_{0.1} (x) = - 1

What is the answer to solvefor y,x=3log_{y}(2) ?
The answer to solvefor y,x=3log_{y}(2) is y=2^{3/x} {x<0\lor x>0}