What is the answer to log_{e}(x)+4=log_{e}(x+6) ?

The answer to log_{e}(x)+4=log_{e}(x+6) is x= 6/(e^4-1)

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log_{e}(x)+4=log_{e}(x+6)

lo g_{e} (x) + 4 = lo g_{e} (x + 6)

x = \frac{6}{e ^{4} - 1}

Decimal Notation

x = 0.11194 \dots

Solution steps

lo g_{e} (x) + 4 = lo g_{e} (x + 6)

Apply log rules

x e^{4} = x + 6

Solve

x e^{4} = x + 6 : x = \frac{6}{e ^{4} - 1}

x = \frac{6}{e ^{4} - 1}

Verify Solutions:

x = \frac{6}{e ^{4} - 1}

True

The solution is

x = \frac{6}{e ^{4} - 1}

lo g_{2} (x) - lo g_{2} (16) = 3

n = ln^{2} (x)

lo g_{8} (X) = \frac{1}{3}

5 ln (6 x - 2) + 13 = 23

lo g_{x} (25) = lo g_{5} (125) - 1

What is the answer to log_{e}(x)+4=log_{e}(x+6) ?
The answer to log_{e}(x)+4=log_{e}(x+6) is x= 6/(e^4-1)