What is the answer to 2ln(x)=ln^2(x) ?

The answer to 2ln(x)=ln^2(x) is x=e^2,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2ln(x)=ln^2(x)

2 ln (x) = ln^{2} (x)

x = e^{2}, x = 1

Decimal Notation

x = 7.38905 \dots, x = 1

Solution steps

2 ln (x) = ln^{2} (x)

Rewrite the equation with

ln (x) = u

2 u = u^{2}

Solve

2 u = u^{2} : u = 2, u = 0

u = 2, u = 0

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = 2 : x = e^{2}

Solve

ln (x) = 0 : x = 1

x = e^{2}, x = 1

Verify Solutions:

x = e^{2}

True

, x = 1

True

The solutions are

x = e^{2}, x = 1

lo g_{7} (x) + lo g_{7} (x - 48) = 2

0.88 = ln (y)

lo g_{4} (x) + 5 lo g_{2} (x) - 36 = 0

lo g_{10} (d) = 3.7 - 0.2 \cdot 20

lo g_{x} (3 x^{2} - 13 x + 15) = 2

What is the answer to 2ln(x)=ln^2(x) ?
The answer to 2ln(x)=ln^2(x) is x=e^2,x=1
Solve for x: 2ln(x)=ln^2(x)
The solution is x=e^2,x=1