What is the answer to 2log_{3}(x)+log_{3}(8)=7 ?

The answer to 2log_{3}(x)+log_{3}(8)=7 is x=3^{(7-3log_{3}(2))/2}

Solve for x: 2log_{3}(x)+log_{3}(8)=7

The solution is x=3^{(7-3log_{3}(2))/2}

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2 lo g_{3} (x) + lo g_{3} (8) = 7

x = 3^{\frac{7 - 3 l o g _{3} ( 2 )}{2}}

Decimal Notation

x = 16.53405 \dots

Solution steps

2 lo g_{3} (x) + lo g_{3} (8) = 7

Move

lo g_{3} (8)

to the right side

2 lo g_{3} (x) = 7 - lo g_{3} (8)

Divide both sides by

2

lo g_{3} (x) = \frac{7 - lo g _{3} ( 8 )}{2}

Apply log rules

x = 3^{\frac{7 - 3 l o g _{3} ( 2 )}{2}}

Verify Solutions:

x = 3^{\frac{7 - 3 l o g _{3} ( 2 )}{2}}

True

The solution is

x = 3^{\frac{7 - 3 l o g _{3} ( 2 )}{2}}

x, ln (x) = - ln (y) - y + c

x, 1 + lo g_{2} (- 5 x) = 4

x, lo g_{2} (6 x + 4) = 1

lo g_{y} (25) = 2

ln (x) + ln (7 x) = 4

What is the answer to 2log_{3}(x)+log_{3}(8)=7 ?
The answer to 2log_{3}(x)+log_{3}(8)=7 is x=3^{(7-3log_{3}(2))/2}
Solve for x: 2log_{3}(x)+log_{3}(8)=7
The solution is x=3^{(7-3log_{3}(2))/2}