What is the answer to log_{4}(x)=log_{4}(x+1)+2 ?

The answer to log_{4}(x)=log_{4}(x+1)+2 is No Solution for x\in\mathbb{R}

Solve for x: log_{4}(x)=log_{4}(x+1)+2

The solution is No Solution for x\in\mathbb{R}

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lo g_{4} (x) = lo g_{4} (x + 1) + 2

No Solution for x \in R

Solution steps

lo g_{4} (x) = lo g_{4} (x + 1) + 2

Apply log rules

x = (x + 1) \cdot 16

Solve

x = (x + 1) \cdot 16 : x = - \frac{16}{15}

x = - \frac{16}{15}

Verify Solutions:

x = - \frac{16}{15}

False

The solution is

No Solution for x \in R

lo g_{10} (x) = - 14.108

2 lo g_{a} (x) = lo g_{a} (16) + 4

ln (x + \frac{1}{2}) = ln (2 x + 1)

- 35 = 10 lo g_{10} (\frac{x}{1})

lo g_{10} (lo g_{10} (x)) = 4

What is the answer to log_{4}(x)=log_{4}(x+1)+2 ?
The answer to log_{4}(x)=log_{4}(x+1)+2 is No Solution for x\in\mathbb{R}
Solve for x: log_{4}(x)=log_{4}(x+1)+2
The solution is No Solution for x\in\mathbb{R}