What is the answer to solvefor x,ln(y)=ln(x)+x ?

The answer to solvefor x,ln(y)=ln(x)+x is x=\W(y)

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solvefor x,ln(y)=ln(x)+x

solve for

x, ln (y) = ln (x) + x

x = W (y)

Solution steps

ln (y) = ln (x) + x

Switch sides

ln (x) + x = ln (y)

Move

x

to the right side

ln (x) = ln (y) - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{l n (y) - x}

Simplify

e^{l n (x)} : x

Simplify

e^{l n (y) - x} : e^{- x} y

x = e^{- x} y

Solve

x = e^{- x} y : x = W (y)

x = W (y)

Verify Solutions:

x = W (y)

True

The solution is

x = W (y)

lo g_{3} (- 2 x + 6) = lo g_{3} (x - 2)

6 lo g_{8} (3 x + 1) = lo g_{8} (64)

x = lo g_{3} (x)

(x) 6 - 5 ln (x) = 2

ln (\frac{1}{x}) = 1.147629

What is the answer to solvefor x,ln(y)=ln(x)+x ?
The answer to solvefor x,ln(y)=ln(x)+x is x=\W(y)